Invert Binary Tree【226】

Datetime:2016-08-23 01:23:27          Topic: LeetCode           Share

226. Invert Binary Tree

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Total Accepted:  57653 Total Submissions:  136144 Difficulty:  Easy

Invert a binary tree.

4
   /   \
  2     7
 / \   / \
1   3 6   9

to

4
   /   \
  7     2
 / \   / \
9   6 3   1

Trivia:

This problem was inspired by  this original tweet by  Max Howell

:

Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.

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Tree
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
 //以下是别人家的算法:自己当时实在没想清楚根据给定的代码形式如何写出反转程序
 //后序递归算法:
class Solution {
public:
//将根节点反转,并获取翻转后该根节点的指针
     TreeNode* invertTree(TreeNode* root) {
        if(root == NULL){   
             return NULL;
        }else{
            //这样做将:树的底层先被真正交换,然后其上一层才做反转
            TreeNode* newleft = invertTree(root->right);
            TreeNode* newright = invertTree(root->left);
            root->left = newleft;
            root->right = newright;
            return root;
        }
    } 
};

参考资源:

【1】博客地址,http://www.cnblogs.com/ganganloveu/p/4640933.html





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